Thanks! I previously found that my videos roughly fit a power-law distribution, and the one academic paper I could find on the subject also found that views were Zipf-distributed.
Since power law distributions are scale-invariant, I think it’s relatively easy to answer your question: p(100M|1M)∝p(100|1) etc. In that original post I thought that my personal views roughly fit the model P(Views≥10k)=0.3k−2; I haven’t looked at that recently though and expect the coefficients have changed.
Thanks! I previously found that my videos roughly fit a power-law distribution, and the one academic paper I could find on the subject also found that views were Zipf-distributed.
Since power law distributions are scale-invariant, I think it’s relatively easy to answer your question: p(100M|1M)∝p(100|1) etc. In that original post I thought that my personal views roughly fit the model P(Views≥10k)=0.3k−2; I haven’t looked at that recently though and expect the coefficients have changed.